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-3x^2+1230x-210x+72000=0
We add all the numbers together, and all the variables
-3x^2+1020x+72000=0
a = -3; b = 1020; c = +72000;
Δ = b2-4ac
Δ = 10202-4·(-3)·72000
Δ = 1904400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1904400}=1380$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1020)-1380}{2*-3}=\frac{-2400}{-6} =+400 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1020)+1380}{2*-3}=\frac{360}{-6} =-60 $
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